Does any one know of a mathematical formula to find the resultant angle of legs and spindles on a chair? I have a table of resultant angles form the book ‘The Chairmaker’s Workshop’ by Drew Langsner, but would like to see how these angles can be derived mathematically.
Replies
"Resultant angle" is a generic term, so there are different formulas depending on the situation. Let me know if the below is not what you're looking for.
Assume we have a leg or spindle that is angled A degrees from the vertical when viewing the front elevation, and B degrees from the vertical when viewing the side elevation. Then the angle of the leg or spindle when viewed in plan, C, is:
C = tan-1 ( sin B / sin A )
And the resultant angle D (the angle of the leg or spindle in its own plane) is:
D = sin-1 ( sin2 A + sin2 B)1/2
For example, if A = 5° and B = 15°, then C is 71.4° (in plan view, with the front of the object at the bottom, and 0° being due east), and D is 15.8°.
-Steve
I'll give it a try,
Thanks
C = tan-1 ( sin B / sin A )
And the resultant angle D (the angle of the leg or spindle in its own plane) is:
D = sin-1 ( sin2 A + sin2 B)1/2
For example, if A = 5° and B = 15°, then C is 71.4° (in plan view, with the front of the object at the bottom, and 0° being due east), and D is 15.8°.
Steve.. Do you design aeroplanes? I cracked up on that reply! You just made my day with a good belly laugh... I love Math but not that good at it!
Thank you for making my day a bit better with a smile on my face.. I Really loved it!...
Edited 6/9/2009 6:50 pm by WillGeorge
"Do you design aeroplanes?"
No, but over the years I have designed lasers, cyclotron power supplies for medical imaging, ground support equipment for satellites, and gas handling equipment for nuclear weapons-grade tritium, among other things.
Why do you ask?
-Steve
Why do you ask? I just read your post and I had a good day!
I can do almost anything with my OLD HANDS . My mind does not work with my hands so I am not a good carver..
Your words.. Why do you ask? Because I thought you may have been a designer of the tactical Nuke weapons we had in 1960 or thereabouts that would wipe out both sides! I was in Germany then and we all knew if we fired the weapon we went with the so called enemy..
And I asked just because I found the post funny! I do not understand math! I try but my little brain just likes women and wood...
I think some hate for me and I wonder why?
The "Why do you ask?" part was just a joke. I knew why you asked...
-Steve
I think I understand... Huggs!
"gas handling equipment for nuclear weapons-grade tritium, among other things"
Steve, When I was in the military as nuclear weapons tech one of the procedures we performed would be changing out the tritium canisters on the war heads. The tritium detectors were set to go off at one parts per million, that is some nasty gas. Your design resume is very impressive.
Tom
We never dealt with the real stuff; we leak-checked everything with helium, and then it all got shipped off to Savannah River for final assembly and testing. As I recall, the leak requirement was 10-12 l-atm / sec, meaning that it would take over 30,000 years for one litre of gas to escape.
-Steve
Ran the numbers and its the formula I’m looking for.
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Thanks
I'm confused. Steve Schafer gave you the formula in his first reply.
He sure did and I responded by telling him I would give it a try. Now that I ran the numbers I wanted him to know that the formula was the correct one since in his first reply he was concerned that it may not be what I was looking for.
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Is that okay?
Sorry, it was the present test (I am) that led me to think you were still looking for the formula. My confusion.
Don’t you mean “present tense”?
yes--just another example of how typo's and small glitches can end up wrong.
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